GE 350-017614-133 E工控處理器模塊庫存

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型號：GE 350-017614-133 E
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GE 350-017614-133 E工控處理器模塊庫存

抽汽和進(jìn)汽圖在將汽輪機的抽汽/進(jìn)氣蒸汽圖編程控制，它必須具有交點A、B和C（參見圖4-6）。
如果A點和B點已經(jīng)存在，需要的轉(zhuǎn)換是擴展
LP=0線和零抽汽和進(jìn)汽流線，直到它們交叉或
相交（這是編程的C點）。如果點A不存在，則擴展
LP=100管線和零抽汽和進(jìn)汽管線，直到：
交叉或相交是編程的點A。
如果B點和C點不存在，則必須修改地圖以包含B點
&C.需要創(chuàng)建LP=0行。要創(chuàng)建LP=0行，必須：
了解通過汽輪機后端所需的小蒸汽流量。在里面
在我們的示例蒸汽圖（圖4-6）中，小所需流量為8000 lb/h（3629kg/h）。
手動85018V1 505E數(shù)字調(diào)速器
伍德沃德123
1.延長大提取線。參見圖4-6。
2.延長零提取和進(jìn)線。
3.找到渦輪機的小后端蒸汽流量（這將是C點的HP流動）。
4.標(biāo)記零提取和進(jìn)氣流線與汽輪機的小后端蒸汽流量。該標(biāo)記將為C點，用于：編程。
5.通過步驟4中創(chuàng)建的標(biāo)記，繪制一條平行于LP=100線的線。
這將是您的LP=0管線或LP閥門關(guān)閉管線。6.標(biāo)記大提取線與創(chuàng)建的LP=0的交點線這將是編程的B點。
控制需要A、B和C點來計算渦輪機的內(nèi)部
壓力比和極限。所需的十個值可從轉(zhuǎn)換后的蒸汽圖中獲取。舉例
使用圖4-6中的蒸汽圖，如下所示。
大功率值是S=100線與S軸交叉的負(fù)載
（在我們的示例中約為10496 kW）。
大HP流量值是HP=100線穿過HP軸的流量（約54000 lb/h；24494 kg/h）。
點A是P=0、extr/adm和LP=100線相交的位置（大功率@0EXTR/ADM＝約11625kW；大HP流量@0 EXTR/ADM=約62000磅/小時；28123kg/h）。
大吸入量=約20000磅/小時（9072千克/小時）。
點B是LP=0和P=100線相交的地方（小功率@MAX
提取=約1504kW；大抽汽時的小高壓流量=約28000磅/小時；12701kg/h）。
點C是LP=0和零提取和進(jìn)氣流線相交的位置
（零提取/進(jìn)入時的小功率=約-205 kW；小HP零提取/進(jìn)入流量=約8000 lb/h；3629kg/h）。
另一個參數(shù)，小HP升程（%）也將設(shè)置為4000/54000=7.4%.Extraction & Admission Steam Map
Before a turbine’s extraction/admission steam map can be programmed into the
control, it must have the intersection points A, B, & C (refer to Figure 4-6).
If points A & B already exist, the only conversion necessary is the extension of
the LP=0 line and the zero extraction and admission flow line until they cross or
intersect (this is Point C for programming). If point A does not exist, the extension
of the LP=100 line and the zero extraction and admission flow line until they
cross or intersect is Point A for programming.
If points B & C do not exist, your map will have to be modified to include points B
& C. The LP=0 line will need to be created. To create the LP=0 line you must
know the minimum required steam flow through the back-end of the turbine. In
our example steam map (Figure 4-6) the minimum required flow was 8000 lb/h
(3629 kg/h).
Manual 85018V1 505E Digital Governor
Woodward 123
1. Extend the maximum extraction line. Refer to Figure 4-6.
2. Extend the zero extraction & admission line.
3. Find your turbine’s minimum back-end steam flow (this will be point C’s HP
flow).
4. Mark the intersection of the zero extraction & admission flow line and the
turbine’s minimum back-end steam flow. This mark will be Point C for
programming.
5. Draw a line parallel to the LP=100 line, through the mark created in step 4.
This will be your LP=0 line or LP valve closed line.
6. Mark the intersection of the maximum extraction line and the created LP=0
line. This will be Point B for programming.
Points A, B, and C are required by the control to calculate the turbine’s internal
pressure ratios and limits. The ten values needed can be taken from the converted steam map. An example
has been provided below, using the steam map in Figure 4-6.
The MAX POWER value is the load where the S=100 line crosses the s-axis
(about 10 496 kW in our example).
The MAX HP FLOW value is the flow where the HP=100 line crosses the HPaxis (about 54 000 lb/h; 24 494 kg/h).
Point A is where the P=0 extr/adm and LP=100 lines intersect (MAX POWER @
0 EXTR/ADM = about 11 625 kW; MAX HP FLOW @ 0 EXTR/ADM = about
62 000 lb/h; 28 123 kg/h).
MAX ADMISSION = about 20 000 lb/h (9072 kg/h).
Point B is where the LP=0 and P=100 lines intersect (MIN POWER @ MAX
EXTRACTION = about 1504 kW; MIN HP FLOW @ MAX EXTRACTION = about
28 000 lb/h; 12 701 kg/h).
Point C is where the LP=0 and zero extraction & admission flow lines intersect
(MIN POWER @ ZERO EXTRACTION/ADMISSION = about -205 kW; MIN HP
FLOW @ ZERO EXTRACTION/ADMISSION = about 8000 lb/h; 3629 kg/h).
An additional parameter, MIN HP LIFT (%), would also be set to 4000/54000 =
7.4%.

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